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Examples: Capacitors in Circuits

Example 1:

Capacitors of 1F and 2.2F are connected in series.

Determine the effective capacitance of the circuit.

Using "product over sum" gives:

C = (C1 x C2) / (C1 + C2)

thus C = (1 x 2.2) / (1 + 2.2) F

therefore C = 2.2 / 3.2 = 0.69F

Example 2:

Capacitors of 2.2F, 3.3F and 4.7F are connected in parallel.

Determine the effective capacitance of the circuit.

The effective capacitance will be given by:

C = C1 + C2 + C3 = 2.2 + 3.3 + 4.7 = 10.2 F

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Page last modified on July 21, 2011, at 10:32 AM