<^< Capacitance | Course Index | Electric Field Strength >^>
It should now be apparent that an electric field will appear within the capacitor whenever a potential difference is applied to the plates. At the same time, a positive charge will appear on one of the plates and an equal (but opposite) charge will appear on the other.
The value of the charge present, Q, is:
- Directly proportional to the capacitance of the capacitor (the larger the capacitance the larger the charge)
- Directly proportional to the voltage between the capacitor plates (the larger the voltage the larger the charge).
In fact, the charge on a capacitor is given by:
Q = C V
Where Q is the charge in Coulomb, C is the capacitance (in Farad) and V is the voltage (in Volts).
<^< Capacitance | Course index | Electric Field Strength >^>
