Two parallel plates are separated by an air gap of 25 mm.
Determine the electric field strength if the potential difference between the plates is 600V.
The electric field strength will be given by:
E = V / d = 600 / (25 x 10-3) = 24 kV / m
Example 2:
Two parallel plates separated by an air gap of 2 mm. If the plates have a capacitance of 1 nF and an electric field of 400 kV/m is applied to them, determine the charge that will be stored in the capacitor.
