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Example 1:
Inductors of 10mH, 22mH and 60mH are connected in series.
Determine the effective inductance of the circuit.
In the series circuit,
L = L1 + L2 + L3
thus
L = 10mH + 22mH + 60mH = 92mH
Example 2:
Inductors of 60mH and 100mH are connected in parallel.
Determine the effective inductance of the circuit.
Using "product over sum" gives,
L = (L1 x L2) / (L1 + L2)
thus L = (60 x 100) / (60 + 100) mH
therefore L = 6,000 / 160 = 37.5 mH
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