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Example 1:
A transistor operates with a collector current of 18 mA and a base current of 0.5 mA.
Determine the value of emitter current.
In this case, IC = 18 mA and IB = 0.5 mA.
Now IE = IB + IC thus IE = (18 + 0.5) = 18.5 mA.
Example 2:
A transistor operates with a collector current of 2.5 mA.
If the emitter current is 2.58 mA determine the base current.
In this case, IC = 2.5 mA and IE = 2.58 mA.
Now IE = IB + IC thus IB = IE - IC from which IB = (2.58 - 2.5) = 0.08 mA.
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